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3x^2-125x+625=0
a = 3; b = -125; c = +625;
Δ = b2-4ac
Δ = -1252-4·3·625
Δ = 8125
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{8125}=\sqrt{625*13}=\sqrt{625}*\sqrt{13}=25\sqrt{13}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-125)-25\sqrt{13}}{2*3}=\frac{125-25\sqrt{13}}{6} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-125)+25\sqrt{13}}{2*3}=\frac{125+25\sqrt{13}}{6} $
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